Httpwebrequest Bilderupload / Multipart POST

breakdown17

Grünschnabel
Hallo Zusammen,

ich arbeite zurzeit an einem Programm mithilfe dessen ich Bilder in meine Facebook-Gruppe hochladen kann. Das posten von Text funktioniert soweit ohne Probleme, allerdings weiß ich nicht, wie ich mithilfe von httpwebrequest Bilder hochladen kann.

Wäre klasse wenn ihr mir helfen könntet. :)
 

breakdown17

Grünschnabel
Bin glaube ich nahe an einer Lösung.

Diese Infos habe ich von HTTP-Liveheaders:
Code:
Content-Type: multipart/form-data; boundary=---------------------------6306511023357
Content-Length: 11316

-----------------------------6306511023357
Content-Disposition: form-data; name="fb_dtsg"

AQGkqeWzPJ4C
-----------------------------6306511023357
Content-Disposition: form-data; name="charset_test"

â?¬,´,â?¬,´,æ°´,Ð?,Ð?
-----------------------------6306511023357
Content-Disposition: form-data; name="file1"; filename="156928_318983771550461_1084321640_n.jpg"
Content-Type: image/jpeg

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K‰Rì{LÊJë[`ˆØ›/lÇj>Ý0c }å© ;]ƒ7Š—C~ NN(¿©·£ÀÂ&<ƒQío7ÑÔBd† 1݆»)Ùíè%¡kpŒ¼KE—™yÜXžæ>ÛŠ¸_CUW]ââvŽ3˜5ÐÁÀÜÌ‹nc*Jî9çˆá]£A~B¸€í%¼†£áì8è¡ž(JÏjÈúÉ
!RŒz,Í°¢òkõqèc]ZÌ@T.ðIG ˆÅ‹ÔQj7¿h÷ËÆ´f*\ÏóPÙtñ;Âé½Dù7æv¶»s R„C¥*…á¯S šDnXǤ£FZÑqßGÛ¦
nªÅ„NýO°´ì8É Œ{_Ü ¦u‚¨ÁâÝø%Ë‹.g*ØÇ’bêùÍEÝU;€ví))…Ø¡²°_ðæ™Bƒ$xîoXçuщ ø®*KFŸ^z™V‡Šò9øï ì$-]
—.\X¹óo˜A'3ÏŸá•ìû•˜sï…W›I¦2ØmâBÙ-肯*×5AR¦ôÀHüK4bäšÆyAƒo¿i•G&eË—.4Œ]71þå‡***{æêWK—w¸©Î8«–ìÁ¥÷#² ÷š%ÅvmuG‰›}Ÿð:5†Ôt0W“ólŽNËt<ž…Þ6ø23˜ºBl¿â-²ã W½ã•sWû˜?n=¢²ÝEVëÚ<RáòY3 š
ß#‰ŸmCêZâðkþTZ?kù¡A(±+Sy~½;Ï••±)ùeæ
Ò8'b&^]KQfŸ1ض®MÁSlh/,¿©ÿÙ
-----------------------------6306511023357
Content-Disposition: form-data; name="file2"; filename=""
Content-Type: application/octet-stream

-----------------------------6306511023357
Content-Disposition: form-data; name="file3"; filename=""
Content-Type: application/octet-stream

-----------------------------6306511023357
Content-Disposition: form-data; name="caption"

my message
-----------------------------6306511023357
Content-Disposition: form-data; name="return_uri"

/groups/343423129098473?view=group&fc=photo_upload_success
-----------------------------6306511023357
Content-Disposition: form-data; name="return_uri_error"

https://m.facebook.com/photos/upload/?target_id=343423129098473&upload_source=composer
-----------------------------6306511023357
Content-Disposition: form-data; name="target"

343423129098473
-----------------------------6306511023357
Content-Disposition: form-data; name="ref"

m_upload_pic
-----------------------------6306511023357
Content-Disposition: form-data; name="album_fbid"

-----------------------------6306511023357--


Meine Postdaten sehen bis jetzt so aus:
Code:
Content-Type: multipart/form-data; boundary=-----------------------------635337969091495151

-----------------------------635337969091495151
Content-Disposition: form-data; name="fb_dtsg"

AQHqzAUyxK8X
-----------------------------635337969091495151
Content-Disposition: form-data; name="charset_test"

****?,****,****?,****,****?,****,****
-----------------------------635337969091495151
Content-Disposition: form-data; name="file1"; filename="156928_318983771550461_1084321640_n.jpg"
Content-Type: image/jpeg

d?
-----------------------------635337969091495151
Content-Disposition: form-data; name="file2"; filename=""
Content-Type: application/octet-stream

-----------------------------635337969091495151
Content-Disposition: form-data; name="file3"; filename=""
Content-Type: application/octet-stream

-----------------------------635337969091495151
Content-Disposition: form-data; name="caption"

my message
-----------------------------635337969091495151
Content-Disposition: form-data; name="return_uri"

/groups/343423129098473?view=group&fc=photo_upload_success
-----------------------------635337969091495151
Content-Disposition: form-data; name="return_uri_error"

https://m.facebook.com/photos/upload/?target_id=343423129098473&upload_source=composer
-----------------------------635337969091495151
Content-Disposition: form-data; name="target"

343423129098473
-----------------------------635337969091495151
Content-Disposition: form-data; name="ref"

m_upload_pic
-----------------------------635337969091495151
Content-Disposition: form-data; name="album_fbid"

-----------------------------635337969091495151--

Wie man sieht wird das Bild nicht richtig übergeben. Er übermittelt nur:
d?

Mein code sieht wie folgt aus:
Code:
Dim boundary2 As String = "-----------------------------" & DateTime.Now.Ticks.ToString & vbCrLf
Dim boundary3 As String = "-----------------------------" & DateTime.Now.Ticks.ToString & "--"
Dim request As HttpWebRequest = DirectCast(WebRequest.Create("https://upload.facebook.com/_mupload_/composer/?site_category=m_basic&waterfall_id=53accb1103576908a26290cc98a72409&source_loc=composer_group"), HttpWebRequest)

request.Method = "POST"
request.KeepAlive = True
request.CookieContainer = tempCookies
request.ContentType = "application/x-www-form-urlencoded"
request.Referer = "https://m.facebook.com/groups/" & test
request.UserAgent = "Mozilla/5.0 (Windows; U; Windows NT 6.1; ru; rv:1.9.2.3) Gecko/20100401 Firefox/4.0 (.NET CLR 3.5.30729)"

Dim BoundaryBytes() As Byte = System.Text.Encoding.ASCII.GetBytes(("Content-Type: multipart/form-data; boundary=" & boundary2 & vbCrLf))

Dim InfoBytes() As Byte = System.Text.Encoding.ASCII.GetBytes("Content-Disposition: form-data; name=""fb_dtsg""" & vbCrLf & dtsg & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""charset_test""" & vbCrLf & vbCrLf & "â?¬,´,â?¬,´,æ°´,Ð?,Ð?" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""file1""; filename=""156928_318983771550461_1084321640_n.jpg""" & vbCrLf & "Content-Type: image/jpeg" & vbCrLf)

Dim FurtherBytes() As Byte = System.Text.Encoding.ASCII.GetBytes((vbCrLf & boundary2 & "Content-Disposition: form-data; name=""file2""; filename=""""" & vbCrLf & "Content-Type: application/octet-stream" & vbCrLf & vbCrLf & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""file3""; filename=""""" & vbCrLf & "Content-Type: application/octet-stream" & vbCrLf & vbCrLf & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""caption""" & vbCrLf & vbCrLf & TextBox9.Text & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""return_uri""" & vbCrLf & vbCrLf & "/groups/343423129098473?view=group&fc=photo_upload_success" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""return_uri_error""" & vbCrLf & vbCrLf & "https://m.facebook.com/photos/upload/?target_id=343423129098473&upload_source=composer" & vbCrLf & boundary2 & vbCrLf & "Content-Disposition: form-data; name=""target""" & vbCrLf & vbCrLf & "343423129098473" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""ref""" & vbCrLf & vbCrLf & "m_upload_pic" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""album_fbid""" & vbCrLf & vbCrLf & vbCrLf & boundary3))

request.ContentLength = BoundaryBytes.Length & InfoBytes.Length & FurtherBytes.Length

Dim FileInfo As New IO.FileInfo("C:\Users\Timo\Pictures\156928_318983771550461_1084321640_n.jpg")
request.ContentLength += FileInfo.Length
Dim RequestStream As IO.Stream = request.GetRequestStream

RequestStream.Write(BoundaryBytes, 0, BoundaryBytes.Length)
RequestStream.Write(InfoBytes, 0, InfoBytes.Length)

Dim FileStream As IO.FileStream = IO.File.Open("C:\Users\Timo\Pictures\156928_318983771550461_1084321640_n.jpg", _
IO.FileMode.Open)

Dim Buffer(1024) As Byte
Dim BytesRead As Integer

Do
BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)
RequestStream.Write(Buffer, 0, BytesRead)
RequestStream.Write(FurtherBytes, 0, FurtherBytes.Length)
Loop Until BytesRead = 0
FileStream.Close()
RequestStream.Close()

Dim postresponse As HttpWebResponse

postresponse = DirectCast(request.GetResponse(), HttpWebResponse)
tempCookies.Add(postresponse.Cookies)
logincookie = tempCookies
Dim postreqreader As New StreamReader(postresponse.GetResponseStream())

Als fehler erhalte ich:
Die Anfrage wurde abgebrochen: Die Anfrage wurde abgebrochen..

Zeile:
RequestStream.Close()

Wäre echt klasse wenn ihr mir helfen könntet :)
 

Bullja

Erfahrenes Mitglied
Das geht auf jedenfall in die richtige Richtung.

In Deiner "do until loop" ist allerdings ein Fehler:
Code:
Do
BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)
RequestStream.Write(Buffer, 0, BytesRead)
###Diese Zeile ist fehl am Platz: RequestStream.Write(FurtherBytes, 0, FurtherBytes.Length)
Loop Until BytesRead = 0

Der Dateiinhalt muss erst komplett in den request stream geschrieben werden. Danach erst können mit FurtherBytes weitere Parts geschrieben werden.
 

breakdown17

Grünschnabel
Danke Bullja für die Antwort. Habe das ganze jetzt so angepasst:
Code:
            Dim FileStream As IO.FileStream = IO.File.Open("C:\Users\grimmtim\Pictures\1156928_318983771550461_1084321640_n.jpg", _
              IO.FileMode.Open)

            Dim Buffer(1024) As Byte
            Dim BytesRead As Integer

            Do
                BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)
            Loop Until BytesRead = 0
            RequestStream.Write(Buffer, 0, BytesRead)
            RequestStream.Write(FurtherBytes, 0, FurtherBytes.Length)

allerdings hängt sich das Programm jetzt auf, wenn ich das Bild übermitteln möchte und nach einer langen Zeit kommt:
Timeout für Vorgang überschritten

Das Bild hat nur eine Größe von 9,55kb daher denke ich nicht dass es so lange benötigt um das Bild zu übertragen
 

Spyke

Premium-User
ich hab gerade ein verständnis problem mit:
Code:
            Do
                BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)
            Loop Until BytesRead = 0
wird da nicht immer wieder der Buffer überschrieben ? ? ? ?

Edit: Editiert weil aus mehreren ? ****** wurde ^^
 

breakdown17

Grünschnabel
Ich habe BytesRead = FileStream.Read(Buffer, 0, Buffer.Length) mal aus der schleife rausgenommen. Allerdings bekomme ich nun wieder: Die Anfrage wurde abgebrochen: Die Anfrage wurde abgebrochen..

Zeile: RequestStream.Close()

code:
Code:
Dim Buffer(1024) As Byte
        Dim BytesRead As Integer


        BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)

        RequestStream.Write(Buffer, 0, BytesRead)
        RequestStream.Write(FurtherBytes, 0, FurtherBytes.Length)
        FileStream.Close()
        RequestStream.Close()

Der teil davor ist unverändert.
 

Bullja

Erfahrenes Mitglied
Richtig sollte es so aussehen:
Code:
Do
    BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)
    RequestStream.Write(Buffer, 0, BytesRead)
Loop Until BytesRead = 0

Der Fehler dürfte aber das Programm nicht mit "Die Anfrage wurde abgebrochen" abbrechen.
 

breakdown17

Grünschnabel
Danke. :)
Allerdings kommt immernoch die gleiche Fehlermeldung.

Das wird nun übergeben:
Code:
Content-Type: multipart/form-data; boundary=-----------------------------635344076476314667


-----------------------------635344076476314667
Content-Disposition: form-data; name="fb_dtsg"


-----------------------------635344076476314667
Content-Disposition: form-data; name="charset_test"

€,´,€,´,æ°´,Ô,Ä
-----------------------------635344076476314667
Content-Disposition: form-data; name="file1"; filename="156928_318983771550461_1084321640_n.jpg"
Content-Type: image/jpeg

tŸ¤Øƒih\ÝOzL‚ÍõVk¹”vÄ¥šÇUÓG„Qaxs"¨=ª§/zGésìà´•4±É!,—à.±ŽwøºËÏ
X,nU“RÆÆ’_¶ëˆÇú@È‹©hŸ™ÃÖ¼—Hí)Ø™>ñ*&¦ 5{}ëÉ]UPç]ÓÈO2â«Ï!Ó;½ëU=pÕEõÚ=ª&¦"=qæµ0@ÆÓÆ×7Pо
ÀØÚÐ
-----------------------------635344076476314667
Content-Disposition: form-data; name="file2"; filename=""
Content-Type: application/octet-stream


-----------------------------635344076476314667
Content-Disposition: form-data; name="file3"; filename=""
Content-Type: application/octet-stream


-----------------------------635344076476314667
Content-Disposition: form-data; name="caption"


-----------------------------635344076476314667
Content-Disposition: form-data; name="return_uri"

/groups/343423129098473?view=group&fc=photo_upload_success
-----------------------------635344076476314667
Content-Disposition: form-data; name="return_uri_error"

https://m.facebook.com/photos/upload/?target_id=343423129098473&upload_source=composer
-----------------------------635344076476314667
Content-Disposition: form-data; name="target"

343423129098473
-----------------------------635344076476314667
Content-Disposition: form-data; name="ref"

m_upload_pic
-----------------------------635344076476314667
Content-Disposition: form-data; name="album_fbid"


-----------------------------635344076476314667--

Das Bild scheint noch immer nicht richtig übergeben zu werden :/


Aktueller Code:
Code:
 Dim tempCookies As New CookieContainer
        tempCookies = logincookie

        Dim boundary2 As String = "-----------------------------" & DateTime.Now.Ticks.ToString & vbCrLf
        Dim boundary3 As String = "-----------------------------" & DateTime.Now.Ticks.ToString & "--"
        ' Do the request
        Dim request As HttpWebRequest = DirectCast(WebRequest.Create("https://upload.facebook.com/_mupload_/composer/?site_category=m_basic&waterfall_id=53accb1103576908a26290cc98a72409&source_loc=composer_group"), HttpWebRequest)
        request.UserAgent = "Mozilla/5.0 (Windows; U; Windows NT 6.1; ru; rv:1.9.2.3) Gecko/20100401 Firefox/4.0 (.NET CLR 3.5.30729)"
        request.Method = "POST"
        request.KeepAlive = True
        request.CookieContainer = tempCookies
        request.Referer = "https://m.facebook.com/photos/upload/?target_id=343423129098473&upload_source=composer"
        request.ContentType = "Content-Type: multipart/form-data; " & boundary2
        Dim BoundaryBytes() As Byte = System.Text.Encoding.Default.GetBytes(("Content-Type: multipart/form-data; boundary=" & boundary2 & vbCrLf))
        Dim InfoBytes() As Byte = System.Text.Encoding.Default.GetBytes("Content-Disposition: form-data; name=""fb_dtsg""" & vbCrLf & dtsg & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""charset_test""" & vbCrLf & vbCrLf & "â?¬,´,â?¬,´,æ°´,Ð?,Ð?" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""file1""; filename=""1156928_318983771550461_1084321640_n.jpg""" & vbCrLf & "Content-Type: image/jpeg" & vbCrLf)
        Dim FurtherBytes() As Byte = System.Text.Encoding.Default.GetBytes((vbCrLf & boundary2 & "Content-Disposition: form-data; name=""file2""; filename=""""" & vbCrLf & "Content-Type: application/octet-stream" & vbCrLf & vbCrLf & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""file3""; filename=""""" & vbCrLf & "Content-Type: application/octet-stream" & vbCrLf & vbCrLf & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""caption""" & vbCrLf & vbCrLf & "mein text" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""return_uri""" & vbCrLf & vbCrLf & "/groups/645391745509569?view=group&fc=photo_upload_success" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""return_uri_error""" & vbCrLf & vbCrLf & "https://m.facebook.com/photos/upload/?target_id=645391745509569&upload_source=composer" & vbCrLf & boundary2 & vbCrLf & "Content-Disposition: form-data; name=""target""" & vbCrLf & vbCrLf & "645391745509569" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""ref""" & vbCrLf & vbCrLf & "m_upload_pic" & vbCrLf & boundary2 & "Content-Disposition: form-data; name=""album_fbid""" & vbCrLf & vbCrLf & vbCrLf & boundary3))
        request.ContentLength = BoundaryBytes.Length & InfoBytes.Length & FurtherBytes.Length
        Dim FileInfo As New IO.FileInfo("C:\Users\Timo\Pictures\2\192-444-414-960-3236581.jpg")
        request.ContentLength += FileInfo.Length

        Dim RequestStream As IO.Stream = request.GetRequestStream

        RequestStream.Write(BoundaryBytes, 0, BoundaryBytes.Length)
        RequestStream.Write(InfoBytes, 0, InfoBytes.Length)


        Dim FileStream As IO.FileStream = IO.File.Open("C:\Users\Timo\Pictures\2\192-444-414-960-3236581.jpg", _
          IO.FileMode.Open)

        Dim Buffer(1024) As Byte
        Dim BytesRead As Integer


        Do
            BytesRead = FileStream.Read(Buffer, 0, Buffer.Length)
            RequestStream.Write(Buffer, 0, BytesRead)
        Loop Until BytesRead = 0


        RequestStream.Write(FurtherBytes, 0, FurtherBytes.Length)
        FileStream.Close()
        RequestStream.Close()
        Dim HttpWebResponse As Net.HttpWebResponse = request.GetResponse


Eigentlich müsste das Bild so übergeben werden:
Code:
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 $.' ",#(7),01444'9=82<.342ÿÛ C			

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Aber es übergibt nur das:
Code:
tŸ¤Øƒih\ÝOzL‚ÍõVk¹”vÄ¥šÇUÓG„Qaxs"¨=ª§/zGésìà´•4±É!,—à.±ŽwøºËÏ
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ÀØÚÐ
 
Zuletzt bearbeitet:

Bullja

Erfahrenes Mitglied
Funktionert der POST ohne das Bild? Falls der Fehler ohne Bild immer noch auftaucht, liegt ein anderes Problem vor.
Wenns auch ohne Bild nicht funktioniert, dann mal ein so kleines Programm wie möglich erstellen und damit beginnen den Fehler zu finden.
 

breakdown17

Grünschnabel
Ok ich glaub das problem war das hier:
request.ContentLength = BoundaryBytes.Length & InfoBytes.Length & FurtherBytes.Length

Ich habe das & in + geändert jetzt kommt kein Fehler mehr. Allerdings wird noch immer kein Bild hochgeladen :/